Given the equation:
[tex]6-x=y[/tex]
we can write the values that are missing on the table if we make x = 0 and x = 2 and solve for y separately. We have the following:
[tex]\begin{gathered} x=0 \\ \Rightarrow6-0=y \\ \Rightarrow y=6 \\ x=2 \\ \Rightarrow6-2=y \\ \Rightarrow y=4 \end{gathered}[/tex]
notice that if x = 0, then y = 6, and if x = 2, then y = 4.
For the last box, now we have that y = 2, substituting this value on the equation we get:
[tex]\begin{gathered} y=2 \\ \Rightarrow6-x=2 \end{gathered}[/tex]
to solve for x, we can add 'x' on both sides of the equation, and then move the 2 on the right side to the left side. By doing this, the sign of the 2 will change to negative:
[tex]\begin{gathered} 6-x=2 \\ \Rightarrow6-x+x=2+x \\ \Rightarrow6=2+x \\ \Rightarrow6-2=x \\ \Rightarrow4=x \end{gathered}[/tex]
therefore, if y = 2, then x = 4
