Question

Susan has a jar of jellybeans. She has 10 yellow, 5 green, 3 red, and 2 black jellybeans. What is the probability thatshe will get a yellow jellybean on her first grab, replace it, and then grab a black jellybean on her second grab?Write your answer in simplest form.оO 20O 30о3

Answer 1

The probability formula is given by:

$\text{ P(E) =}\frac{\text{ N(Required outcome)}}{\text{ N(Total outcome)}}$

Number of yellow jellybeans, n(Y) = 10

Number of green jellybeans, n(G) = 5

Number of red jellybeans, n(R) = 3

Number of black jellybeans, n(B) = 2

Total number of balls = 10 + 5 + 3 + 2 = 20 balls

P( she gets a yellow jellybean first, replaces it, and grabs a black jellybean)

$\begin{gathered} \text{ P(gets a yellow jellybean) =}\frac{10}{20} \\ \text{ P(grabs a black jellybean) =}\frac{2}{20} \end{gathered}$$\text{ P( yellow first, black second with replacement) =}\frac{10}{20}\times\frac{2}{20}\text{ =}\frac{1}{20}$

Therefore, the answer to the probability that susan gets a yellow jellybean on her first grab, replaces it, and grabs a black jellybean is 1/20