The probability of selecting a 6, given that a blue disk is selected is given by the following formula:
[tex]P(B|A)=P(A\text{ n B\rparen/P\lparen A\rparen}[/tex]
There are 4 blue in : 1, 2 , 6, 8
P(A)= blue disk selected:
P(B)= 6 is selected
[tex]P(A)=\frac{4}{8}=\frac{1}{2}.[/tex]
[tex]P(A\text{ }n\text{ B})=P(A)*P(B)=\frac{1}{2}*\frac{1}{4}=\frac{1}{8}[/tex]
Where P(B) is the probablity to select the number 6 in four blue disks.
Substituing:
[tex]\begin{gathered} P(A|B)=(\frac{1}{8})\text{ /\lparen1/2\rparen} \\ \\ P(A|B)=\frac{1}{4} \end{gathered}[/tex]
Answer: The probablity to select a 6, given that a blue disk was selected is: 1/4.