Question

If this proportion is correct what is the probability that in a random sample of 4 customers at anitas exactly 2 order their food to go

Answer 1

Anita's report that 45% of its customer order their food to go.

If the proportion is correct, then 55% of its customer eat in the restaurant.

Thus, the probability that exactly 2 order their food to go is;

$\begin{gathered} P(E)=^nC_r(p)^r(1-p)^{n-r} \\ P(\text{exactly two)= }^4C_2(0.45)^2(1-0.45)^{4-2} \\ P(\text{exactly two)= }6(0.2025)(0.3025) \\ P(\text{exactly two)= }0.368 \end{gathered}$