Question

Zeros algebra two help

Answer 1

we have the function

$y=\frac{x^2+7x+10}{x+3}$

Remember that

The zeros of the function, are the values of x when the value of y=0

so

For y=0

$x^2+7x+10=0$

Solve the quadratic equation

we have that

x^2+7x+10=(x+5)(x+2)

therefore

the zeros of the function are

(-5,0) and (-2,0)