We can solve the equation as:
[tex]x^2+x-2=0[/tex][tex]\begin{gathered} x=\frac{-1\pm\sqrt[]{1^2-4\cdot1\cdot(-2)}}{2\cdot1} \\ x=\frac{-1\pm\sqrt[]{1+8}}{2} \\ x=\frac{-1\pm\sqrt[]{9}}{2} \\ x=\frac{-1\pm3}{2} \\ x_1=\frac{-1-3}{2}=-\frac{4}{2}=-2 \\ x_2=\frac{-1+3}{2}=\frac{2}{2}=1 \end{gathered}[/tex]Answer: The solution for this equation is x=-2 and x=1.
