Question

which of the following functions has a graph in which the vertex and axis of symmetry are to the left of the vertex and axis of symmetry of the graph of f (x) =(x - 1)^2+ 1 select all that apply

Answer 1

B, E, F

1) Considering that f(x) = (x-1)²+1 , then the Vertex is at V=(1, 1) because y= a(x-h)+k The Vertex is at (h, k) and the axis of symmetry is at x =h

f(x), V=(1, 1) axis of symmetry x= 1

Examining looking for V (h, k) and x=h

a) V (1,1)

b) V (-1,-2) axis x=-1

c) V (1,2) axis: x= -1 (to the left)

d) V ( 2, 1)

e) V (-2,2) axis x =-2 (to the left)

f) V (-1,2) axis x=-1

2) Hence, the answers are B, E, F for those equations show a vertex and consequently an axis to the left of g(x).