Question

Jim will rent a car for the weekend . He can choose one of two plans . The first plan has no initial fee but costs $0.70 per mile driven . The second plan has an initial fee of $55 and costs an additional $0.50 per mile driven . How many miles would Jim need to drive for the two plans to cost the same ?

Answer 1

SOLUTION:

Case: Word problem System of equations)

Method:

Let x be the number of miles they both run

First plan:

Total cost: Initial fee + Cost for total mile driven

y=0 + 0.70x

y= 0.70x

Second plan:

Total cost: Initial fee + Cost for total mile driven

z= 55 + 0.50x

When the costs are equal, y =z

Hence:

0.07x = 55 + 0.50x

0.7x - 0.5x = 55

0.2x = 55

$\begin{gathered} x=\frac{55}{0.2} \\ x=275 \end{gathered}$

Final answer:

The number of miles Jim needs to drive for the two plans to cost the same is 275 miles