We are given the following equation:
[tex]C=\frac{1}{3}h(s+b)[/tex]To solve for "s" we will first multiply both sides by 3:
[tex]3C=h(s+b)[/tex]Now we divide both sides by h:
[tex]\frac{3C}{h}=s+b[/tex]Now we subtract b to both sides:
[tex]\frac{3C}{h}-b=s[/tex]And thus we solve for "s".