Hello, I need some help with Part 2 question 5! Please show work as the instructions asked! I included other completed work from the assignment for extra information.



SOLUTION
The given polynomial is:
[tex](x+7)(x-2)^2(x^2-4)(x+1)^4[/tex]Using differece of squares, it follows:
[tex]\begin{gathered} (x^2-4) \\ =\lparen x^2-2^2) \\ =(x-2)(x+2) \end{gathered}[/tex]Substituting the expression into the given polynomial gives:
[tex](x+7)(x-2)^2(x-2)(x+2)(x+1)^4[/tex]Thus the polynomial becomes:
[tex](x+7)(x-2)^3(x+2)(x+1)^4[/tex]Using the Fundamental Theorem of Algebra the number of roots of the polynomial is equal to the degree of the polynomial.
Thus the number of roots is:
[tex]1+3+1+4=9[/tex]Therefore the number of roots is 9.
Notice that the factor with multiplicity of 3 is (x-2)
Therefore the code piece is E