Answer:
Explanation:
Let the number = x
[tex]\begin{gathered} \text{The difference of the number and 2}=x-2 \\ The\text{ square root }=\sqrt{x-2} \\ 5\text{ more than the square root}=\sqrt[]{x-2}+5 \end{gathered}[/tex]The result is 13, therefore, we have the equation:
[tex]\sqrt[]{x-2}+5=13[/tex]We solve the equation for x:
Subtract 5 from both sides.
[tex]\begin{gathered} \sqrt[]{x-2}+5-5=13-5 \\ \sqrt[]{x-2}=8 \end{gathered}[/tex]Next, square both sides:
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