The vertex format = a(x - h)^2 + k
where (h,k) is the vertex of quadratics
so, from the graph (h,k) = (-2, 8)
so,
y = a(x - h)^2 + k = a(x - (-2))^2 + 8
y = a ( x + 2)^2 + 8
as shown the graph pass through (0 , 0)
substitute with (0,0) to find a
so,
0 = 4a + 8
4a = -8
a = -2
y = -2 ( x + 2)^2 + 8
check by another point (-4 , 0)
if x = -4
y = -2 ( -4 + 2)^2 + 8 = -2 * 4 + 8 = -8 + 8 = 0
So, the answer is true
