The given area of the square is:
[tex]A=150\text{ units\textasciicircum2}[/tex]The area of a square is given by the formula:
[tex]A=s^2[/tex]If we replace the given value we obtain:
[tex]\begin{gathered} 150=s^2 \\ s=\sqrt{150} \end{gathered}[/tex]The result of this square root is not an integer, and the closest square roots that are exact numbers are:
[tex]\begin{gathered} \sqrt{144}<\sqrt{150}<\sqrt{169} \\ 12<\sqrt{150}<13 \end{gathered}[/tex]As the rational numbers need to be within 1/8 inch of the actual side length, it is:
[tex]x<\frac{\sqrt{150}}{8}[/tex]As the square root of 150 is between 12 and 13, we can use any two whole numbers that are less than 13 and divide by 8 to obtain a number less than sqrt(150)/8, for example, 12:
[tex]\begin{gathered} \frac{12}{8}<\frac{\sqrt{150}}{8} \\ \\ \text{ Simplify} \\ \frac{\frac{12}{4}}{\frac{8}{4}}=\frac{3}{2} \end{gathered}[/tex]Now, another number could be 10, so:
[tex]\begin{gathered} \frac{10}{8}<\frac{\sqrt{150}}{8} \\ \\ \text{ Simplify} \\ \frac{\frac{10}{2}}{\frac{8}{2}}=\frac{5}{4} \end{gathered}[/tex]Two rational numbers that are within 1/8 inch of the actual side length could be: 3/2 and 5/4