We have the system of equations:
[tex]\mleft\{\begin{aligned}x=2y-5\text{ (equation 1)} \\ -3x=-6y+15\text{ (equation 2)}\end{aligned}\mright.[/tex]Notice that in (equation 1) the variable x is already clear. Let's substitute in (equation 2), so we can find the value of y:
[tex]\begin{gathered} -3x=-6y+15 \\ \rightarrow-3(2y-5)=-6y+15 \\ \rightarrow-6y+15=-6y+15 \end{gathered}[/tex]Notice that this is true for any value of y
Thereby, the system has infinite solutions
