Question

Beginning the questionA single number is chosen from the digits 1 through 30. Find the probability that the number is an even number or a number divisible by 3

Answer 1

Let:

A = Choose an even number or a number divisible by 3

n = Number of favourable events

m = Total outcomes

The Number of favourable events is:

n = Amount of even numbers from 1 to 30 plus amount of numbers divisible by 3 from 1 to 30. so:

$n=15+10=25$

So:

$P(A)=\frac{n}{m}=\frac{25}{30}=\frac{5}{6}\approx0.83$

Answer:

Approximately 83.3%