Answer
D. 29
Explanation
Given:
mass of lead (m) = 15 g
heat (Q) = ?
Specific heat of lead (Cp) = 0.13 J/g°C
Initial temperature = 22 °C
Final temperature = 37 °C
Required: Heat required to increase the temperature.
Solution
To solve this problem, use the following formula:
Q = m x Cp x ΔT where Q is the heat, Cp is the specific heat, m is the mass and Δ T is the change in temperature
Q = 15 g c x 0.13 J/g°C x (37-22°C)
Q = 29.25 J
