It is given that one third of restaurant is given away and the value that remains is $15000.
If one third is gone that means two thirds of the restaurant is valued at $15000.
Let the value of the restaurant be x.
[tex]\begin{gathered} \frac{2}{3}x=15000 \\ x=15000\times\frac{3}{2} \\ x=22500 \end{gathered}[/tex]So the original value of the restaurant was $22,500.
Option A is correct.