Question

At bob bakery he sells three type of cookies to his customers chocolate chip,sugar, and peanut butter in the past hour. Bob sold 5 times as many chocolate chips cookies as peanut butter. Bob sold 7 fewer sugar cookies than chocolate cookiesBob sold 9 peanut butter How many chocolate chip he sold How many sugar cookies he sold How many peanut butter he sold

Answer 1

45 Chips chocolates cookies

38 sugar cookies

9 peanut butter cookies

Explanation

Step 1

make the equations:

let

x represents the number of chocolate chips cookies he sold

y represents the number of sugar cookies he sold

z represents the number of peanut butter cookies he sold

hence, let's traslate

a)Bob sold 5 times as many chocolate chips cookies as peanut butter

$x=5z\Rightarrow equation(1)$

b)Bob sold 7 fewer sugar cookies than chocolate cookies

$y=x-7\Rightarrow equation(2)$

c)Bob sold 9 peanut butter

$z=9\Rightarrow equation(3)$

Step 2

solve the equations

a) replace the z value from equation (3)

$\begin{gathered} x=5z\Rightarrow equation(1) \\ x=5(9) \\ x=45 \end{gathered}$

therefore, he sold 45 chips chocolate cookies

b)now, replace the x value into equation (2) to find y

$\begin{gathered} y=x-7\Rightarrow equation(2) \\ y=45-7 \\ y=38 \end{gathered}$

it means he sold 38 sugar cookes

I hope this helps you