Solution:
Given the sequence;
[tex]1,2,3,4,5,6,7,8,...[/tex]A sequence with a common difference d, is called an Arithmetic Sequence.
[tex]\begin{gathered} a_n=n^{th\text{ }}term \\ \\ a_1=first\text{ }term=1 \\ \\ a_2=second\text{ t}erm=2 \\ \\ d=a_2-a_1 \\ \\ d=2-1 \end{gathered}[/tex]
The nth term of an arithmetic sequence is generally given as;
[tex]\begin{gathered} a_n=a_1+d(n-1) \\ Where\text{ }n\text{ }means\text{ }number\text{ }of\text{ }terms \end{gathered}[/tex]Thus, in the problem, the first term, the common difference are known. Then, we would substitute the value into the nth term formula. We have;
[tex]a_n=1+1(n-1)[/tex]Then, simplify further;
[tex]\begin{gathered} a_n=1+n-1 \\ a_n=1-1+n \\ a_n=n \end{gathered}[/tex]ANSWER:
[tex]The\text{ }n^{th}\text{ }term\text{ }a_n\text{ }is\text{ }n[/tex]