I need some help solving this practice problem from my trigonometry prep guide* I got six as the answer, let me know if I was originally correct..

I need some help solving this practice problem from my trigonometry prep guide I got six as the answer let me know if I was originally correct class=

Respuesta :

Amplitude is the one half of the difference between the maximum and minimum values of y.

From the graph, the maximum value is 6 and minimum value is -6.

Find the amplitude.

[tex]\begin{gathered} \text{Amplitude}=\frac{1}{2}(6-(-6)) \\ =\frac{1}{2}\cdot12 \\ =6 \end{gathered}[/tex]

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