Given expression is
[tex]4\times(\frac{3}{4}-\frac{1}{2})+3\times6[/tex]
Recall that the order of operations is
1. Paratheses
2. Exponents.
3. Multiplication.
4. Division.
5. Addition.
6. Subtraction.
First, we need to solve inside the paratheses.
LCM of 4 and 2 is 4, making the denominator 4, we get
[tex]4\times(\frac{3}{4}-\frac{1}{2})+3\times6=4\times(\frac{3}{4}-\frac{1\times2}{2\times2})+3\times6[/tex]
[tex]=4\times(\frac{3}{4}-\frac{2}{4})+3\times6[/tex]
[tex]=4\times(\frac{3-2}{4})+3\times6[/tex]
[tex]=4\times\frac{1}{4}+3\times6[/tex]
Second, we need to solve multiplication.
Multiply 3 and 6, we get
[tex]=4\times\frac{1}{4}+18[/tex]
Multiply 4 and 1, we get
[tex]=\frac{4}{4}+18[/tex]
Third, we need to solve division.
Divide 4 into 4, we get
[tex]=1+18[/tex]
Fourth, we need to solve addition.
Add 1 and 18, we get
[tex]=19[/tex]
Hence the answer is 19.
Option A is correct.
