Answer:
[tex]64\text{ \%}[/tex]
Explanation:
Here, we want to get the mass of the anhydrous compound in the given hydrate
To get this, we have to divide the molar mass of the hydrate part by the molar mass of the whole hydrate and write it as a percentage
The molar mass of the water part is (5 * 18 g/mol = 90 g/mol: The molar mass of 1 mol of water is 18 g/mol)
The molar mass of CuSO4 is 160 g/mol
The percentage by mass is thus:
[tex]\frac{160}{160+90}\times\text{ 100 = 64\%}[/tex]
