Question

A committee must be formed with 4 teachers and 4 students. If there are 6 teachers to choose from, and 12 students, how many different ways could the committee be made?

Answer 1

A committee must be formed with 4 teachers and 4 students. If there are 6 teachers to choose from and 12 students, how many different ways could the committee be made?

step 1

Find out the combination 4C6 (teachers)

$4C6=\frac{6!}{4!(6-4)!}=15$

step 2

Find out the combination 4C12 (students)

$4C12=\frac{12!}{4!(12-4)!}=495$

step 3

Multiply 15 by 495

15*495=7,425 ways

therefore

the answer is 7,425 ways