The equation of a line in poins slope form is given by:
[tex]y-y_1=m(x-x_1)[/tex]where m is the slope and (x1,y1) is a point on the line. Plugging the values the problem gives we have:
[tex]\begin{gathered} y-4=-6(x-(-2)) \\ y-4=-6(x+2) \end{gathered}[/tex]Therefore, the equation in point slope form is:
[tex]y-4=-6(x+2)[/tex]