Question

2. A school club sold children's and adults' tickets to a fundraiser. Children's tickets sold for $3.50 each, and adults' tickets sold for $7.50 each. The club sold a total of 62 tickets and collected a total of $365.00. How many children's tickets were sold?A. 19D. 42B. 25C. 37

Answer 1

ANSWER

$B.\text{ }25$

EXPLANATION

Let the number of children's tickets be x.

Let the number of adults' tickets be y.

The total number of tickets sold is 62. Therefore, we have that:

$x+y=62$

The total amount collected is $365.00. This implies that:

$3.50x+7.50y=365.00$

Now, we have two simultaneous equations:

$\begin{gathered} x+y=62 \\ 3.50x+7.50y=365.00 \end{gathered}$

From the first equation, make y the subject of the formula:

$y=62-x$

Substitute that into the second equation and solve for x:

$\begin{gathered} 3.50x+7.50(62-x)=365.00 \\ \\ 3.50x+465.00-7.50x=365.00 \\ \\ 3.50x-7.50x=365.00-465.00 \\ \\ -4.00x=-100.00 \\ \\ x=\frac{-100.00}{-4.00} \\ \\ x=25 \end{gathered}$

Therefore, 25 children's tickets were sold. The correct answer is option B.