Question

PC15 (8) + H₂O(1) → POCl3 (1) + 2HCl(aq)When 64.23 g of phosphorus pentachloride reacts with ewhat mass of hydrogen chloride will be produced?If needed, enter scientific notation with the "e". For examwould be entered as 1.44e7.Answer:g HCI.

Answer 1

Answer:

22.52g of hydrogen chloride will be produced.

Explanation:

1st) From the balanced reaction we know that 1 mole of PCl5 reacts with 1 mole of water to produce 1 mole of POCl3 and two moles of hydrogen chloride. Using the molar mass of PCl5 (208.24g/mol) and HCl (36.5g/mol) we can convert the moles to grams:

- 1 mole of PCl5 weighs 208.24g.

- 2 moles of HCl weigh 73g

2nd) With the grams of PCl5 and HCl from the stoichiometry, and the given value of 64.23g of PCl5, we can calculate the mass of HCl that will be produced:

$\begin{gathered} 208.24gPCl_5-73gHCl \\ 64.23gPCl_5-x=\frac{64.23gPCl_5*73gHCl}{208.24gPCl_5} \\ x=22.52gHCl \end{gathered}$

Finally, 22.52g of hydrogen chloride will be produced.