Question

in triangle ABC, a=14m b=12m, and B=49 find all possible values of A

Answer 1

ANSWER

A = 62 degrees

EXPLANATION

Given:

A triangle with side a = 14 m, b = 12m and angle B = 49 degrees.

Result:

Angle A

Using sine rule

$\begin{gathered} \frac{sinA}{a}=\frac{sinB}{b} \\ \end{gathered}$$\begin{gathered} sinA=\frac{asinB}{b} \\ sinA=\frac{14sin49}{12} \\ sinA=\frac{14\times0.7548}{12} \\ sinA=0.8805 \\ A=\sin^{-1}0.8805 \\ A=61.7^0 \end{gathered}$

Hence,