Question

Please help!!! I need to factor the expression by grouping, but I messed up and gave an equation instead

Answer 1

Given the expression

$y^3-4y^2-8y+32$

Take outside the square of y from the first two terms and -8 and from the last two terms.

$y^2(y-4)-8(y-4)$

The term y-4 is common. So, take it outside.

$(y^2-8)(y-4)$