Given:
[tex]3^{3x-5}=\frac{1}{9^x}[/tex]
Solve the equation,
[tex]\begin{gathered} 3^{3x-5}=\frac{1}{9^x} \\ 3^{3x-5}=\frac{1}{(3^2)^x} \\ 3^{3x-5}=\frac{1}{3^{2x}}^{} \\ 3^{3x-5}=3^{^{-2x}} \\ \text{Apply the exponent rule:} \\ 3x-5=-2x \\ 3x+2x=5 \\ 5x=5 \\ x=1 \end{gathered}[/tex]
Answer: option c)
