Answer:
[tex](x+7)^2+(y+13)^2=36[/tex]Explanation:
The general form of the equation of a circle is given as:
[tex](x-h)^2+(y-k)^2=r^2[/tex]Where:
• The centre = (h,k)
,• The radius =r
Substituting the points:
[tex]\begin{gathered} \mleft(h,k\mright)=\mleft(-7,-13\mright) \\ r=6 \end{gathered}[/tex]We have the equation of the circle to be:
[tex]\begin{gathered} (x-(-7))^2+(y-(-13))^2=6^2 \\ (x+7)^2+(y+13)^2=36 \end{gathered}[/tex]•