Will give brainly if you can Match the exponential graphs to the situations below in which the investmentslose money.$100 at 8% loss per year$200 at 10% loss per year$100 at 10% loss per year$200 at 8% loss per year1st graph (1,180)2nd graph (1,181)3rd graph (1,92)4th (1,90)

Will give brainly if you can Match the exponential graphs to the situations below in which the investmentslose money100 at 8 loss per year200 at 10 loss per yea class=

Respuesta :

a)The formula for the graph of $100 at 8% loss per year will be:

[tex]f(x)=a(1-ppercent)^x[/tex]

So the first graph function is:

[tex]f(x)=100(1-0.08)^x=100(0.92)^x[/tex]

The graph is shown below:The

The point (1,92) lies on this graph.

b) The second graph of $200 at 10% loss per year is given by the equation:

[tex]g(x)=200(1-0.1)^x=200(0.9)^x[/tex]

The graph is shown below:

As seen the point (1,180) lies on second graph.

c) The equation for $100 at 10% loss per year is:

[tex]h(x)=100(1-0.1)^x=100(0.9)^x[/tex]

The graph is shown below:

The point (1,90) lies on this graph.

d) The equation for $200 at 8% loss per year is given by:

[tex]i(x)=200(1-0.08)^x=200(0.92)^x[/tex]

The graph is shown below:

As seen the point (1,184) lies on the graph.

So:

$100 at 8% loss per year has the point (1,92).

$200 at 10% loss per year has the point (1,180).

$100 at 10% loss per year has the point (1,90).

$200 at 8% loss per year has the point (1,184)

Ver imagen MckenzleeC534848
Ver imagen MckenzleeC534848
Ver imagen MckenzleeC534848
Ver imagen MckenzleeC534848
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