What basic trigonometric identity would you use to verify that

Given the equation:
[tex]\frac{\sin^2x+\text{cos}^2x}{\cos x}=\sec x[/tex]Let's determine the trigonometric identity that you could be used to verify the exquation.
Let's determine the identity:
Apply the trigonometric identity:
[tex]\sin ^2x+\cos ^2x=1[/tex][tex]\cos x=\frac{1}{\sec x}[/tex]Replace cosx for 1/secx
Thus, we have:
[tex]\begin{gathered} \frac{\sin^2x+\cos^2x}{\frac{1}{\sec x}} \\ \\ =(\sin ^2x+\cos ^2x)(\sec x) \\ \text{Where:} \\ (\sin ^2x+\cos ^2x)=1 \\ \\ We\text{ have:} \\ (\sin ^2x+\cos ^2x)(\sec x)=1\sec x=\sec x \end{gathered}[/tex]The equation is an identity.
Therefore, the trignonometric identity you would use to verify the equation is:
[tex]\cos ^2x+\sin ^2x=1[/tex]ANSWER:
[tex]\cos ^2x+\sin ^2x=1[/tex]