Respuesta :

Given the equation:

[tex]\frac{\sin^2x+\text{cos}^2x}{\cos x}=\sec x[/tex]

Let's determine the trigonometric identity that you could be used to verify the exquation.

Let's determine the identity:

Apply the trigonometric identity:

[tex]\sin ^2x+\cos ^2x=1[/tex]

[tex]\cos x=\frac{1}{\sec x}[/tex]

Replace cosx for 1/secx

Thus, we have:

[tex]\begin{gathered} \frac{\sin^2x+\cos^2x}{\frac{1}{\sec x}} \\ \\ =(\sin ^2x+\cos ^2x)(\sec x) \\ \text{Where:} \\ (\sin ^2x+\cos ^2x)=1 \\ \\ We\text{ have:} \\ (\sin ^2x+\cos ^2x)(\sec x)=1\sec x=\sec x \end{gathered}[/tex]

The equation is an identity.

Therefore, the trignonometric identity you would use to verify the equation is:

[tex]\cos ^2x+\sin ^2x=1[/tex]

ANSWER:

[tex]\cos ^2x+\sin ^2x=1[/tex]

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