Question

use the quadratic formula to solve the problem: y=2x²+4x-6be sure to show all your work

Answer 1

$x\text{ =}\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

That above is the quadratic formula where

a = 2

b = 4

c = -6

$x=\frac{-4\pm\sqrt[]{4^2-4\times2\times-6}}{2\times2}$$\begin{gathered} x\text{ = }\frac{-4\pm\sqrt[]{16+48}}{4} \\ x=\frac{-4\pm\sqrt[]{64}}{4} \\ x\text{ = }\frac{-4\pm8}{4} \end{gathered}$$\begin{gathered} x\text{ =}\frac{-4\text{ + 8}}{4\text{ }}=\frac{4}{4}=1 \\ or \\ x\text{ = }\frac{-4-8}{4}=\frac{-12}{4}=-3 \end{gathered}$