The rate of the jet in still air is 830mi/hr
The rate of the jet in the wind is 70mi/hr
Let the rate of the jet in still air be x
Let the rate of the jet in wind be y
The formula for calculating distance traveled is expressed as:
[tex]\begin{gathered} \text{distance}=\text{speed}\times\text{time} \\ d=st \end{gathered}[/tex]If a jet travels 3800 miles against the wind in 5 hours, the rate of the jet will be expressed as:
[tex]\begin{gathered} 3800=5(x-y) \\ x-y=760 \end{gathered}[/tex]If the same jet travels 4500 miles with the wind in the same amount of time, the rate of the jet will be expressed as:
[tex]\begin{gathered} 4500=5(x+y) \\ x+y=900 \end{gathered}[/tex]Solve the equations simultaneously
x - y = 760
x + y = 900
Add both equations to have:
x + x = 760 + 900
2x = 1660
x = 1660/2
x = 830mi/hr
Since x - y = 760, hence;
y = x - 760
y = 830 - 760
y = 70mi/hr
Hence the rate of the jet in still air is 830mi/hr and the rate of the jet in the wind is 70mi/hr