Question

Find the complete factored form of the polynomial:22m6 – 12n6

Answer 1

We have to factorized this polynomial.

To do that we can look for common factors between the two terms.

We decomposed each term as:

$\begin{gathered} 22m^6=2\cdot11\cdot m^6 \\ 12n^6=2\cdot2\cdot3\cdot m^6 \end{gathered}$

So only the factor 2 is common to both terms, so we can write the polynomial as:

$22m^6-12n^6=2(11m^6-6n^6)$

Answer: 2*(11m^6-6n^6)