Question

I got this question wrong already once and I just got a new one but im struggling to solve it, so please help me if possible.

Answer 1

$\begin{gathered} x=\sqrt[]{2t} \\ y=2t-3 \end{gathered}$

From the first equation, we have:

$t=\frac{x^2}{2}$

Here, we must take in consideration that x can't be negative, sinte we derive this relation from a square root function.

Replacing t with this result in the parametric function for y, we have:

$\begin{gathered} y=2\frac{x^2}{2}-3 \\ y=x^2-3 \end{gathered}$

Answer:

Option A: The rectangular equation is y = x²-3 with the restriction x>=0