Please help me on this question Drop down 1:Is on the x-axisIs on the y-axisIs on the graph of y = 1/3x + 6Is on the graph of y = 4Is on the coordinate planeDrop down 2:Located at (0,0)On both linesOn the x-axisOn the y-axisOn one lineDrop down 3:EndIntersectCross the x-axisCross the y-axisDrop down 4:EndIntersectCross the x-axisCross the y-axisDrop down 5:SolutionCoefficientDrop down 6:0TrueFalsePositiveNegative

Please help me on this question Drop down 1Is on the xaxisIs on the yaxisIs on the graph of y 13x 6Is on the graph of y 4Is on the coordinate planeDrop down 2Lo class=

Respuesta :

Solution:

The coordinates (-6, 4) satisfy the equation:

[tex]y=\frac{1}{3}x+6[/tex]

because

[tex]\begin{gathered} when\text{ x = -6, we have} \\ y=\frac{1}{3}(-6)+6=-2+6 \\ \Rightarrow y=4 \\ (-6,\text{ 4\rparen is on the graph of y=}\frac{1}{3}x+6 \end{gathered}[/tex]

If (-6, 4) satisfies the equations of two lines, (-6, 4) is

[tex]on\text{ both lines}[/tex]

so that the lines will

[tex]intersect[/tex]

at (-6, 4).

This means that if two lines

[tex]intersect[/tex]

at (-6, 4), then (-6, 4) is the

[tex]solution[/tex]

to the system of equations.

This means that if you substitute -6 for x and 4 for y in the equations, both equation will be

[tex]True[/tex]

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