Given:
The fall height of the water, h=49 m
To find:
The velocity of the water at the turbine.
Explanation:
Let us assume that the initial velocity of the water is u=0 m/s
The water will be falling under the influence of the acceleration of gravity. Thus the acceleration of the water will be g=9.8 m/s².
From the equation of motion,
[tex]v^2=u^2+2gh[/tex]Where v is the velocity of the water at the turbine.
On substituting the known values,
[tex]\begin{gathered} v^2=0+2\times9.8\times49 \\ \Rightarrow v=\sqrt[]{2\times9.8\times49} \\ =31\text{ m/s} \end{gathered}[/tex]Explanation:
The velocity of the water
