Answer:
• The number of advance tickets sold: 25
• The number of same-day tickets sold: 35
Explanation:
Let the number of advance tickets sold = a
Let the number of same-day tickets sold = s
Advance tickets = $25
Same-day tickets = $40.
[tex]\begin{gathered} \text{For one performance, there were 60 tickets sold in all.} \\ a+s=60\ldots(1) \\ \text{The total amount paid from them was }2,025 \\ 25a+40s=2025\ldots(2) \end{gathered}[/tex]From equation (1):
[tex]a=60-s[/tex]Substitute a=60-s into the second equation:
[tex]\begin{gathered} 25(60-s)+40s=2025 \\ 1500-25s+40s=2025 \\ 15s=2025-1500 \\ 15s=525 \\ s=\frac{525}{15} \\ s=35 \end{gathered}[/tex]Recall: a=60-s
[tex]\begin{gathered} a=60-35 \\ a=25 \end{gathered}[/tex]Therefore:
• The number of advance tickets sold: 25
,• The number of same-day tickets sold: 35