Where:
[tex]\begin{gathered} opposite=3 \\ adjacent=5 \\ hypotenuse=\sqrt[]{3^2+5^2}=\sqrt[]{34} \end{gathered}[/tex]So:
[tex]\begin{gathered} \sin (\theta)=\frac{3}{\sqrt[]{34}} \\ \end{gathered}[/tex][tex]\csc (\theta)=\frac{\sqrt[]{34}}{3}[/tex][tex]\cot (\theta)=\frac{5}{3}[/tex]