i inserted a picture of the question, i can give you the answer to question 4 if it helps, all the question go together question 5,6 & 7

• x -intercept,: (0,0) and (60,0)
• Vertex: (30,45)
The roots of the quadratic expression are the x -values in which, in our case, y = 0.
Then:
• r1 = 0
,• r2 = 60
We can substitute these values in the following equation:
[tex]y=a(x-r_1)(x-r_2)[/tex][tex]y=a(x-0_{})(x-60)[/tex]Finally, we can substitute the vertex values in the equation to get a :
[tex]45=a(30)(30-60)[/tex][tex]45=a(30)(-30)[/tex][tex]45=a(-90)[/tex][tex]a=\frac{45}{-90}[/tex][tex]a=-\frac{1}{2}[/tex]Answer:
• 5. ,r1 = 0 and r2 = 60
,• 6.
[tex]y=a(x-0_{})(x-60)[/tex][tex]a=-\frac{1}{2}[/tex][tex]y=-\frac{1}{2}(x-0_{})(x-60)[/tex]• 7.
[tex]45=a(30)(30-60)[/tex]