Problem
Solution
For this case we can solve all the numbers and we got:
[tex]\sqrt[3]{8}=2[/tex]15/5 = 3
12^0 =1
[tex]\sqrt[2]{16}=4[/tex]500 x10 ^-2 = 5
And we can order the values like this:
1<2<3<4<5
And that correspond to:
[tex]12^0<\sqrt[3]{8}<\frac{15}{5}<\sqrt[]{16}<500x10^{-2}[/tex]