A line segment has endpoints (-14/3, -2/3) and (-22/3, -10/3). What is the midpoint of the line segment?A. (-6,-2)B. (-4,-4)C. (-8/3, -16/3)D. (-4/3,-4/3)

Given:
A line segment has endpoints (-14/3, -2/3) and (-22/3, -10/3).
The midpoint of the line segment is,
[tex]\begin{gathered} M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}) \\ (x_1,y_1)=(-\frac{14}{3},-\frac{2}{3}) \\ (x_2,y_2)=(-\frac{22}{3},-\frac{10}{3}) \\ M=(\frac{-\frac{14}{3}-\frac{22}{3}}{2},\frac{-\frac{2}{3}-\frac{10}{3}}{2}) \\ M=(-\frac{36}{6},-\frac{12}{6}) \\ M=(-6,-2) \end{gathered}[/tex]Answer: option a) (-6,-2)