Given:
Principal for both accounts = $2700
Yearly maintenance fees for both accounts = $15
Account 1:
Interest rate, r = 6.6% ==> 0.066
Number of times compounded, n = semiannually = 2
Time, t = 2 years
Account 2:
Interest rate, r = 4.4% ==> 0.044
Number of times compounded, n = quarterly = 4
Time, t = 3 years
Let's determine the investement that will give Vivian the higher profit.
Apply the compound interest formula:
[tex]I=(P(1+\frac{r}{n})^{nt})-P[/tex]Now, let's find the Interest earned in each account.
Account 1:
[tex]\begin{gathered} I=(2700(1+\frac{0.066}{2})^{2\times2})-2700 \\ \\ I=(2700(1.033)^4)-2700 \\ \\ I=3074.43-2700 \\ \\ I=374.43 \end{gathered}[/tex]
Since it has a maintenence fee of $15 yearly, the actual interest will be:
[tex]\begin{gathered} I=374.3-15 \\ \\ I=359.43 \end{gathered}[/tex]The interest earned in account 1 is $359.43
• ACCOUNT 2:
[tex]\begin{gathered} I=(2700(1+\frac{0.044}{4})^{4\times3})-2700 \\ \\ I=2700(1.011)^{12})-2700 \\ \\ I=3078.77-2700 \\ \\ I=378.77 \end{gathered}[/tex]
To find the actual interest given a yearly maintenance fee of $15, we have:
[tex]\begin{gathered} I=378.77-15 \\ \\ I=363.77 \end{gathered}[/tex]The interest earned in account 2 is $363.77
We can see the interest earned in account 2 is greater than that of account 1.
To find the difference, we have:
$363.77 - $359.43 = $4.34
Therefore, account 2 is better because it earns 4.34 more than account 1.
ANSWER:
Account 2 is better because it earns $4.34 more than Account 1.