I need help please I jus need to get this done

Given for the triangle OPQ
[tex]\begin{gathered} PQ=17 \\ QO=9 \\ OP=15 \end{gathered}[/tex]The angle opposite to the side PQ ⇒∠O
The angle opposite to the side QO ⇒∠P
The angle opposite to the side OP ⇒∠Q
The longest side will be opposite to the greatest measure of angle
so, we will arrange the sides from the highest to the least
[tex]PQ>OP>QO[/tex]So, the arrange of the angles from the greatest to the least will be:
[tex]m\angle O>m\angle Q>m\angle P[/tex]So, the answer will be the first option