Question

an ordinary die is cube with numbers 1-6 on the sides. imagine that such a die is rolled twice in succession and that the face values of the two rolls are added together. the sumbis record as the outcome of a random experiment. compute the probability of each event Event A: sum is greater than 7Event B: sum is divided by 4write as a fraction

Answer 1

Explanation

Given that the ordinary die is rolled twice in succession and that the face values of the two rolls are added together. We will have the possible sample space of the result below.

Using this table, we can see that the total number of possible outcomes is given as 36;

Also, Event A occurs 15 times while Event B occurs 9 times.

We can then find the probability below using this formula.

$\text{Probability of an event = }\frac{\text{number of outcomes of the given event}}{Total\text{ number of possible outcomes}}$

Therefore,

$\begin{gathered} Pr\text{(A)= }\frac{15}{36}=\frac{5}{12} \\ Pr(B)=\frac{9}{36}=\frac{1}{4} \end{gathered}$

Answer:

$\begin{gathered} Pr\text{(A)= }\frac{5}{12} \\ Pr(B)=\frac{1}{4} \end{gathered}$