Respuesta :

Answer:

The possible solutions are;

[tex]0,\text{ -3, 3.4, -3.2}[/tex]

Explanation:

Given the inequality;

[tex]-3(2x+7)\leq\frac{1}{2}x[/tex]

Let us solve for x;

[tex]\begin{gathered} -3(2x+7)\leq\frac{1}{2}x \\ \text{expanding;} \\ -6x-21\leq\frac{1}{2}x \\ \text{ multiply through by 2;} \\ 2(-6x)-21(2)\leq2(\frac{1}{2}x) \\ -12x-42\leq x \\ \text{collecting the like terms;} \\ -12x-x\leq42 \\ -13x\leq42 \\ \text{divide both sides by -13;} \\ x\ge\frac{42}{-13} \\ x\ge-3\frac{3}{13} \end{gathered}[/tex]

Therefore, the solution to the inequality is;

[tex]\begin{gathered} x\ge-3\frac{3}{13} \\ or \\ x\ge-3.23 \end{gathered}[/tex]

So, from the options, the possible solutions are;

[tex]0,\text{ -3, 3.4, -3.2}[/tex]

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