Answer:
-$6.72
Explanation:
The cost of the ticket = $10
Let X be the possible profit on the ticket.
The probability distribution for X is given below.
Thus, the expected value for your profit is calculated below:
[tex]\begin{gathered} E(X)=\sum xP(x) \\ =\left(1000\times\frac{1}{800}\right)+\left(300\times\frac{4}{800}\right)+\left(30\times\frac{14}{800}\right) \\ =3.28 \end{gathered}[/tex]
Subtract from 10:
[tex]3.28-10=-\$6.72[/tex]
The expected value for your profit is -$6.72.
Note: This means that if you play the game, you expect to make a loss of $6.72 (rounded to the nearest cent).