Answer:
[tex]x\approx0.64\text{ m}[/tex]Step-by-step explanation:
The weight of the airplane is hanging from the rubber band is represented by the multiplication between its mass (1.3 kg) and the acceleration due to gravity, which is 9.8 m/s^2.
[tex]\begin{gathered} W=m\cdot g \\ W=1.3\cdot9.8 \\ W=12.74\text{ N} \end{gathered}[/tex]This situation can be modeled by Hook's law, which states that the force acting on a spring is given by:
[tex]\begin{gathered} F=kx \\ \text{where,} \\ k=\text{ spring constant} \\ x=displacement\text{ of the spring with respect to its equilibrium position} \end{gathered}[/tex]Substituting the given values, F=12.74 N and k=20 N/m.
Isolate x and solve:
[tex]\begin{gathered} x=\frac{12.74}{20} \\ x=0.637 \\ x\approx0.64\text{ m} \end{gathered}[/tex]
