Step 1:
Write the equation
[tex]\log ^{3x+4}_4\text{ = 2}[/tex]Step 2:
Express the equation in exponential form
[tex]\begin{gathered} \log ^{3x+\text{ 4}}_4\text{ = 2} \\ 3x+4=4^2 \\ 3x\text{ + 4 = 16} \\ 3x\text{ = 16 - 4} \\ 3x\text{ = 12} \\ x\text{ = }\frac{12}{3} \\ x\text{ = 4} \end{gathered}[/tex]Final answer
x = 4
